b^2-2x^2=2xy+y^2

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Solution for b^2-2x^2=2xy+y^2 equation: 


Simplifying
b2 + -2x2 = 2xy + y2

Solving
b2 + -2x2 = 2xy + y2

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '2x2' to each side of the equation.
b2 + -2x2 + 2x2 = 2xy + 2x2 + y2

Combine like terms: -2x2 + 2x2 = 0
b2 + 0 = 2xy + 2x2 + y2
b2 = 2xy + 2x2 + y2

Simplifying
b2 = 2xy + 2x2 + y2

Reorder the terms:
b2 + -2xy + -2x2 + -1y2 = 2xy + -2xy + 2x2 + -2x2 + y2 + -1y2

Combine like terms: 2xy + -2xy = 0
b2 + -2xy + -2x2 + -1y2 = 0 + 2x2 + -2x2 + y2 + -1y2
b2 + -2xy + -2x2 + -1y2 = 2x2 + -2x2 + y2 + -1y2

Combine like terms: 2x2 + -2x2 = 0
b2 + -2xy + -2x2 + -1y2 = 0 + y2 + -1y2
b2 + -2xy + -2x2 + -1y2 = y2 + -1y2

Combine like terms: y2 + -1y2 = 0
b2 + -2xy + -2x2 + -1y2 = 0

The solution to this equation could not be determined.

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